- 0, 1, 2, 3, 4, 5, 6, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 183, 184, 185, 186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211, 212, 213, 214, 259, 260, 261, 262, 263, 264, 265
- 7, 20, 21, 22, 35, 36, 37, 50, 83, 96, 97, 98, 111, 112, 113, 126, 139, 152, 153, 154, 167, 168, 169, 182, 215, 228, 229, 230, 243, 244, 245, 258
- 8, 12, 13, 14, 15, 19, 23, 27, 28, 29, 30, 34, 38, 42, 43, 44, 45, 49, 84, 88, 89, 90, 91, 95, 99, 103, 104, 105, 106, 110, 114, 118, 119, 120, 121, 125, 140, 144, 145, 146, 147, 151, 155, 159, 160, 161, 162, 166, 170, 174, 175, 176, 177, 181, 216, 220, 221, 222, 223, 227, 231, 235, 236, 237, 238, 242, 246, 250, 251, 252, 253, 257
- 9, 11, 16, 18, 24, 26, 31, 33, 39, 41, 46, 48, 85, 87, 92, 94, 100, 102, 107, 109, 115, 117, 122, 124, 141, 143, 148, 150, 156, 158, 163, 165, 171, 173, 178, 180, 217, 219, 224, 226, 232, 234, 239, 241, 247, 249, 254, 256
- 10, 17, 25, 32, 40, 47, 86, 93, 101, 108, 116, 123, 142, 149, 157, 164, 172, 179, 218, 225, 233, 240, 248, 255

- 90
- 32
- 72
- 48
- 24

**Conjecture**: Given any valid set of N go first dice with number of faces x1, x2, ..., xN, it is always possible to generate a new set of go first dice with exactly LCM(x1, x2, ..., xN) faces per die.

This can be done using the following algorithm:

Suppose you have go first dice with the following labels:

- a1, a2, ..., aQ
- b1, b2, ..., bR
- ...
- y1, y2, ..., yZ

- m*a1, m*a1 + 1, ..., m*a1 + (m/Q) - 1, m*a2, m*a2 + 1, ..., m*a2 + (m/Q) - 1, m*aQ, m*aQ + 1, ..., m*aQ + (m/Q) - 1
- m*b1, m*b1 + 1, ..., m*b1 + (m/R) - 1, m*b2, m*b2 + 1, ..., m*b2 + (m/R) - 1, m*bR, m*bR + 1, ..., m*bR + (m/R) - 1
- ...
- m*y1, m*y1 + 1, ..., m*y1 + (m/Z) - 1, m*y2, m*y2 + 1, ..., m*y2 + (m/Z) - 1, m*yZ, m*yZ + 1, ..., m*yZ + (m/Z) - 1

- 1,2,4
- 3,5

- 6*1, 6*1 + 1, 6*2, 6*2 + 1, 6*4, 6*4 + 1
- 6*3, 6*3 + 1, 6*3 + 2, 6*5, 6*5 + 1, 6*5 + 2

- 6, 7, 12, 13, 24, 25
- 18, 19, 20, 30, 31, 32

- 1, 2, 3, 4, 8, 9
- 5, 6, 7, 10, 11, 12

## 2 comments:

I'm losing my ability to read math notation, but I think you're saying that the differing numbers of dice faces can be fixed to be the same by spreading out the values on the faces.

It occurs to me that this makes the "no repeated face values" rule redundant, so long as the requirement of "fairly determining turn order on the first roll" already implies no ties. That is, if values are allowed to repeat on each die but not over multiple dice, there are solutions with smaller numbers that work identically to, say, the given solution.

@cyrebjr, yeah, I think you are correct.

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